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Question re: 10&12 bit color

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SilverE30

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Ditching MMX? It would seem more natural to ditch non saturated integer coding ... but if people really want, they can twiddle the bits and convert it to a 15 bit representation before doing calculations without too much overhead. How about just using the 16 bit format, and including some new C++ types to make working with it without MMX a little easier? A matrix type which presents it as floats, and a 16 bit type with saturation for experimentation? (For when you know you will want to convert the filter to MMX once it is done.) BTW how many fractional bits were you thinking of? (ie. leave room for overbright or not?)

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Conrad
Message # 11 01.04.22 - 20:35:00
RE: Question re: 10&12 bit color

Croak

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BPC: 16. Range: 0 -> 32767. (15 active bits) Last bit (bit 16): Must always be 0. Overbright/Superblack: There will be a 7 bit fraction compared to standard YUV. This means that: 15bpc = (unsigned short)8bpc*128 8bpc = (unsigned char)15bpc/128

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Message # 12 01.04.22 - 20:41:36
RE: Question re: 10&12 bit color

RogRacer

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Bidoche, I just meant you could use operator overloading tricks to perform automatic conversions. Shodan, so basically no overbright ... why not?

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Message # 13 01.04.22 - 20:45:29
RE: Question re: 10&12 bit color

Z3POWER

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@MfA Can you produce some code as a proof of concept ? I fail to see if it will be really useful. @sh0dan No FP rounder ? There are everywhere elsewhere. I'd more likely see: 15bpc = (unsigned short)8bpc*128 + 63 8bpc = (unsigned char)15bpc/128

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Ciao! - - Nathan
Message # 14 01.04.22 - 20:52:11
RE: Question re: 10&12 bit color
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